11х2+7х-4 4х2+11х+6 6х2+13х-19 4у2+3у-22 дискриминат - вопрос №8665260112744211662131942322 от данил2908 20.04.2022 00:13

Question

Алгебра: 11х2+7х-4 4х2+11х+6 6х2+13х-19 4у2+3у-22 дискриминат

данил2908 · Answer

11x^2 + 7x - 4 = 0.D = b^2 - 4ac = 49 - 4*11 * (-4) = 49 + 176 = 225.4x^2 + 11x + 6 = 0.D = b^2 - 4ac = 121 - 4*4*6 = 121 - 96 = 25.6x^2 + 13x - 19 = 0.D = b^2 - 4ac = 169 - 4*6*(-19) = 169 + 456 = 625.4y^2 + 3y - 22 = 0.D = b^2 - 4ac = 9 - 4*4*(-22) = 9 + 352 = 361....