Решить комплексное уравнение: z4-8z2+64=0

Z⁴ - 8z² + 64 = 0
D = 64 - 256 = -192 = 192i²

z² = (8 - 8i√3)/2 = 4 - 4i√3 = 4(1 - i√3) = 4e^(-πi/3)
z₁ = 2e^(-πi/6) = 2(cos(π/6) - i*sin(π/6)) = √3 - i
z₂ = 2e^(5π/6) = 2(cos(5π/6) + i*sin(5π/6)) = -√3 + i

z² = 4 + 4i√3 = 4e^(πi/3)
z₃ = 2e^(πi/6) = 2(cos(π/6) + i*sin(π/6)) = √3 + i
z₄ = 2e^(7πi/6) = 2(cos(7π/6) + i*sin(7π/6)) = -√3 - i

ответ: -√3 - i; -√3 + i; √3 - i; √3 + i