Решите прикрепленное уравнение

log²(0.1) x + 3log(0.1) x = log(3) 81

одз x > 0

81 = 3^4   log(3) 81 = log(3) 3^4 = 4

log(0.1) x = y

y² + 3y  - 4 = 0

D = 9 + 16 = 25

y12 = (-3 +- 5)/2 = -4   1

y1 = 1

log(0,1) x = 1

x = 1/10

y2 = -4

log(0,1) x = -4

x = (0.1)^(-4) = 10^4 = 10000

ответ  x = {1/10, 10000}