1) 5mn+15m-10n-30= 5·(mn+3m-2n-6)= 5·(m·(n+3)-2·(n+3))= 5·(n+3)·(m-2)
2) 256-b^4= (16-b²)·(16+b²)= (4-b)·(4+b)·(16+b²)
1) 5mn+15m-10n-30= 5·(mn+3m-2n-6)= 5·(m·(n+3)-2·(n+3))= 5·(n+3)·(m-2)
2) 256-b^4= (16-b²)·(16+b²)= (4-b)·(4+b)·(16+b²)
5mn+15m-10n-30=5(mn+3m-2n-6)=5(m×(n+3)-2(n+3))=5(n+3)(m-2)