7-х=6х+11 4*(2х+11)-5х=7х+-(х-8) 2*(х-9)=15*(х-3) - вопрос №788629776114211578291536352113542 от verailina1991 12.09.2020 16:23

Question

Алгебра: 7-х=6х+11 4*(2х+11)-5х=7х+-(х-8) 2*(х-9)=15*(х-3) 6*(3х+-5)=2х+11 3*(х-5)-4*(2-х)=6 (х-+8)=7х-12 нужно

verailina1991 · Answer

1) 7 - x = 6x + 11- x - 6x = 11 - 7-7x = 4     x = - 4/72) 4*(2x + 11) - 5x = 7x + (x - 8)8x + 44 - 5x = 7x + x - 83x - 8x = -8 - 44- 5x = - 52       x = 10,43)2*(x - 9) = 15*(x - 3)2x - 18 = 15x - 45- 13x = - 27      x = (2)1/134)6*(3x + 8) - (x - 5) = 2x + 1118x + 48 - x + 5 = 2x + 1115x = - 42     x = - 2,85)3*(x - 5) - 4*(2 - x)= 63x - 15 - 8 + 4x = 67x = 29    x = (4)1/76) (x - 3) - (x - 8) = 7x - 12x - 3 - x + 8 = 7x - 12- 7x = - 17    x = (2)3/7...