4x-3 / 3-2x - 4+5x / 3+2x - 3+x-10x / 4x -9 ,, - вопрос №51539184332453231049 от gavronovaanna2oz9c0h 27.03.2020 11:15

Question

Алгебра: 4x-3 / 3-2x - 4+5x / 3+2x - 3+x-10x / 4x -9 ,, !

gavronovaanna2oz9c0h · Answer

4x-3/3-2x  -  4+5x/3+2x + 3+x-10x^2/9-4x^2 ==((4x-3)(3+2x)-(4+5x)(3-2x)+3+x-10x^2)/  9-4x^2 = =(8x^2 +6x-9+10x^2-12-7x+3+x-10x^2)/  9-4x^2 = =(8x^2 -18)/ 9-4x^2= 2(4x^2 -9)/ 9-4x^2 = -2...

4x-3 / 3-2x - 4+5x / 3+2x - 3+x-10x" / 4x"-9 ,, !