1) lg(x-0.09)+log_0.01(9)=0 2) log_0.25(6x-5)=-2 - вопрос №43033101009001902025652 от German1224 29.04.2020 06:46

Question

Алгебра: 1) lg(x-0.09)+log_0.01(9)=0 2) log_0.25(6x-5)=-2

German1224 · Answer

Lg(x-0,09)+log₀,₀₁9=0   ОДЗ: x-0,09 0  x 0,09lg(x-0,09)+log(10⁻²)9=0lg(x-0,09)+log₁₀⁻²(1/3)⁻²lg(x-0,09)+lg(1/3)=0lg(x-0,09)/(1/3)=03(x-0,09)=1x-0,09=1/3x=0,09+1/3=9/100+1/3=127/300..x=127/300....