х^(2)-0,5x-5<0
x2 - 0.5x - 5 = 0D = b2 - 4acD = 0.25 + 20 = 20.25 = (√20.25)^2
x1,2 = -b ± √D/2ax1 = 0.5 + √20.25/2x2 = 0.5 - √20.25/2ответ: x1 = 0.5 + √20.25/2 ; x2 = 0.5 - √20.25/2
x2 - 0.5x - 5 =a(x-x1)(x+x2)=(x-0.5 + √20.25/2)(x+0.5 - √20.25/2)
(x-0.5 + √20.25/2)(x+0.5 - √20.25/2)<0
21-5=16 а корень из 16 равно 4
4(5х-1.5)>0
20х-6>0
20x>6
x>20/6
х^(2)-0,5x-5<0
x2 - 0.5x - 5 = 0
D = b2 - 4ac
D = 0.25 + 20 = 20.25 = (√20.25)^2
x1,2 = -b ± √D/2a
x1 = 0.5 + √20.25/2
x2 = 0.5 - √20.25/2
ответ: x1 = 0.5 + √20.25/2 ; x2 = 0.5 - √20.25/2
x2 - 0.5x - 5 =a(x-x1)(x+x2)=(x-0.5 + √20.25/2)(x+0.5 - √20.25/2)
(x-0.5 + √20.25/2)(x+0.5 - √20.25/2)<0
21-5=16 а корень из 16 равно 4
4(5х-1.5)>0
20х-6>0
20x>6
x>20/6