Решите систему уравнений 3х - ху = 10 у + ху = 6

3x - xy = 10
y + xy = 6

x(3-y) = 10
y+xy = 6

x = 10/(3-y)

y + 10y/(3-y) = 6

y(3-y) + 10y = 6(3-y)

3y - y2 + 10y = 18 - 6y

y2 - 6y - 13y + 18 = 0

y2 - 19y + 18 = 0

y1 = 18
y2 = 1

x1:
18 + 18x = 6
3 + 3x = 1
x = -2 / 3

x2:
1 + x = 6
x = 5