7x+5 (2x-3)=6 5x-7 (3-x)=2x+11 0, 3-2 (x+1)=0, 4x+0, - вопрос №1576005752365732110321040163273225 от 1анж48 10.03.2022 14:18

Question

Алгебра: 7x+5 (2x-3)=6 5x-7 (3-x)=2x+11 0, 3-2 (x+1)=0, 4x+0, 1 6x-3, 2=7x-3 (2x-2, 5)

1анж48 · Answer

-7x+5 (2x-3)=6

-7x+10x-15=6

3x=21

x=7

5x-7 (3-x)=2x+11

5x-21+7x=2x+11

10x=32

x=3.2

0, 3-2 (x+1)=0, 4x+0, 1

0.3-2x-2=0.4x+0.1

-2.4x=1.8

x= -0.75

6x-3, 2=7x-3 (2x-2, 5)

6x-3.2=7x-6x+7.5

5x=10.7

x= 2.14