No 344 1)x*(x-4)+x-4=0, 2)y*(y+7)-4y-28=0​

1) x1 = 4, x2 = -1; 2) y1 = 4, y2 = -7

Объяснение:

1) x^2-4x+x-4 = 0

x^2-3x-4 = 0

по т.Виета:

x1+x2 = 3

x1*x2 = -4

x1 = 4, x2 = -1

2) y^2+7y-4y-28 = 0

y^2+3y-28 = 0

y1+y2 = -3

y1*y2 = -28

y1 = 4, y2 = -7