X²-3x-4=02x²-8=06x²-12x[tex] {x}^{2} - 2x - 3 - вопрос №92172803402806122230 от dariamisskapri 13.09.2020 05:01

Question

Математика: X²-3x-4=02x²-8=06x²-12x[tex] {x}^{2} - 2x - 3 0[/tex]​

dariamisskapri · Answer

1) Д=9-4*1*(-4)=25х1=(3+5)/2=4х2=(3-5)/2=-12) 2х^2=8х^2=4х1=2х2=-23) 6х(х-2)=06х=0х=0или х-2=0х=24) Д=4+4*3=16х1=(2+4)/2=3х2=(2-4)/2=-1-13 (-беск, - 1), (3,+беск)...

X²-3x-4=02x²-8=06x²-12x​

X²-3x-4=0
2x²-8=0
6x²-12x
${x}^{2} - 2x - 3 > 0$