Даны три точки a (-2.3.1) b(1.-2.3) c(4.-1.0). - вопрос №921567023112341023 от gladiatorcor 26.02.2021 18:32

Question

Математика: Даны три точки a (-2.3.1) b(1.-2.3) c(4.-1.0). найти |2ab+3bc|

gladiatorcor · Answer

AB = (1-(-2), -2-3, 3-1) = (3,-5,2)BC = (4-1, -1-(-2), 0-3) = (3,1,-3)2AB+3BC = 2*(3,-5,2) + 3*(3,1,-3) = (6,-10,4) + (9,3,-9) = (15,-7,-5)|2AB+3AB| = sqrt (225 + 49 + 25) = sqrt (299)...