1) sin^2(3x)=cos^2(3x) 2) tg^3(x)+2tg^2(x)+3tgx=0 - вопрос №907667312323232230 от Aurelli1 12.09.2022 05:13

Question

Математика: 1) sin^2(3x)=cos^2(3x) 2) tg^3(x)+2tg^2(x)+3tgx=0

Aurelli1 · Answer

1) cos^2(3x) = sin^2(3x)cos^2(3x) - sin^2(3x) = cos(6x) = 06x = π/2 + πkx = π/12 + πk/62) tg^3(x) + 2tg^2(x) + 3tg(x) = 0tg(x) * (tg^2 + 2tg(x) + 3) = 0tg(x) = 0x = πktg^2 + 2tg(x) + 3 = 0(tg(x) + 1)^2 + 2 = 0(tg(x) + 1)^2 = -2 — Ø...