Мне 20 коинов n493 1)9-4 2/17+2 3/17= 2)4 3/8+3 - вопрос №829190620493194217231724383781373301591012310 от melnykkatya32 04.12.2020 14:25

Question

Математика: Мне 20 коинов n493 1)9-4 2/17+2 3/17= 2)4 3/8+3 7/8-1 3/7= 3)30-15 9/10-12 3/10= 4)49-19 3/5-2 2/5= 5)29 11/17-4 5/24+10 6/17=

melnykkatya32 · Answer

1) 7 1/172) = (4+3-1) (3*7+7*7-3*8)/56 = 6 46/56 = 6 23/283) 1 4/54) 275) = (29-4+10) (11*24-5*17+6*24)/408 = 35 323/408...