(3целых 2/3 - 1 целая 7/9): (1/2-1/4)+(2 целых 1/2 - вопрос №78728763231791214212134334117 от igoralekseev2 02.07.2020 08:03

Question

Математика: (3целых 2/3 - 1 целая 7/9): (1/2-1/4)+(2 целых 1/2 + 1 целая 3/4)*(3/34+1/17)

igoralekseev2 · Answer

(3целых 2/3 - 1 целая 7/9):(1/2-1/4)+(2 целых 1/2 +1 целая 3/4)*(3/34+1/17)=

=(3 +6/9-(1+7/9)):(2/4-1/4)+(2+2/4+1+3/4)·(3/34+2/34)=(17/9)·4+(17/4)·(5/34)=
=(17·4/9+17·5/(4·34)=(17·4/9+1·5/(4·2))=(17·4·8+5·9)/(9·8)=(544+45)/72=
8 целых 13/72