Реши: а) (3 7/18 - 2 25/36 + 7/48) * 6 6/11 + 1,5+20,15*2 - вопрос №7715540371822536748661115201521510091816 от kuzmichkinvale 13.03.2020 16:26

Question

Математика: Реши: а) (3 7/18 - 2 25/36 + 7/48) * 6 6/11 + 1,5+20,15*2 1/5-10,09 = б (18 1/6-(3,06/7 1/2+3 2/5*0,38))/(19-2 3/8*5 1/3=

kuzmichkinvale · Answer

1) 3 7/18 - 2 25/36 + 7/48 = 3 56/144 - 2 100/144 + 21/144 = 3 77/144 - 2 100/144 = 2 221/144 - 2 100/144 = 121/144
2) 121/144 * 6 6/11 = 121/144 * 72/11 = 11/2 = 5,5
3) 20,15 * 2 1/5 = 20,15 * 2,2 = 44,33
4) 5,5 + 1,5 + 44,33 - 10,09 = 7 + 34,24 = 41,24
ответ 41,24

1) 3 2/5 * 0,38 = 3,4 * 0,38 = 1,292
2) 3,06 : 7 1/2 = 3,06 : 7,5 = 0,408
3) 0,408 + 1,292 = 1,7
4) 18 1/6 - 1,7 = 18 10/60 - 42/60 = 17 70/60 - 42/60 = 17 28/60 = 17 7/15
5) 2 3/8 * 5 1/3 = 19/8 * 16/3 = 38/3 = 12 2/3
6) 17 7/15 : 12 2/3 = 262/15 : 38/3 = 131/95 = 1 36/95
ответ 1 36/95