1) f(x)=4x²-6x, x0=2 2) f(x)=x²-2x, x0=3 3) f(x)=3x²-8x+7, - вопрос №7562010146022203338701434 от oksana78shilki 17.05.2023 08:13

Question

Математика: 1) f(x)=4x²-6x, x0=2 2) f(x)=x²-2x, x0=3 3) f(x)=3x²-8x+7, x0=1 4) f(x)=3x-4x²+20, x0=-2

oksana78shilki · Answer

1. f(x) = 4x^2-6xf`(x) = 8x - 6 f(2) = 8*2 - 6 = 10 2. f(x)=x²-2x, x0=3f`(x) = 2x - 2 f(3) = 2*3 - 2 = 43. f(x)=3x²-8x+7, x0=1f`(x) = 6x - 8 f(1) = 6-8 = -24. f(x)=3x-4x²+20, x0=-2 f`(x) = 3-8x f(2) = 3-(-8) * (-2) = 3 + 16 = 19 ...