Решите ∛х+3=-2 log4 x+log4 (x-3)=1

A)
∛(x+3)=-2
x+3=-8
x=-11
b)
log₄x+log₄(x-3)=1
x>0 i x-3>0⇔x>3⇔x∈(3,∞)

log₄[x(x-3)]=1
x²-3x=4
x²-3x-4=0
Δ=25
x₁=-1∉(3,∞)
x₂=4∈(3,∞)