Реши: а) (3 7/18 - 2 25/36 + 7/48) * 6 6/11 + - вопрос №753087437182253674866111122320212109100 от Елизавета5820 04.06.2020 07:25

Question

Математика: Реши: а) (3 7/18 - 2 25/36 + 7/48) * 6 6/11 + 1 1/2 * 2 3/20 : 2 1/2 + 10 9/100 = б (17 1/18 * 3 3/5 - 119/250 : 14) : (9/100 * 8700-120: 4 2/7) + 153/500 : 3/10 =

Елизавета5820 · Answer

а) (3 7/18 - 2 25/36 + 7/48) * 6 6/11 + 1 1/2 * 2 3/20 : 2 1/2 + 10 9/100 =
=(61/18-97/36+7/48)*72/11+3/2*63/20:5/2+1009/100=
=(8*61/18-4*97/36+3*7/48)*72/11+189/40:5/2+1009/100=
=((488-388+21)/144)*72/11+189/40*2/5+1009/100=
=121/144*72/11+189/100+1009/100=11/2+1198/100=(55+1198)/100=
=1253/100=12 53/100=12,53

б (17 1/18 * 3 3/5 - 119/250 : 14) : (9/100 * 8700-120:4 2/7)+ 153/500 : 3/10=
=(307/18*18/5-119/250*1/14):(783-120*7/30)+153/500*10/3=
=(307/5-119/3500):(783-280)+51/50=(700*307/5-119/3500):503+51/50=
=(214900-119)/3500:503+51/50=214781/3500*1/503+51/50=
=427/3500+51/50=427/3500+70*51/50=(427+3570)/3500=3997/3500=
=1 497/3500=1 71/500