Найдите корни уравнения 4/(3m+1)+(3m-7)/(27m^3+1)=(1-6m)/(1-3m+9m^2) - вопрос №7188998431372731161392 от hhggg1 23.04.2021 12:54

Question

Математика: Найдите корни уравнения 4/(3m+1)+(3m-7)/(27m^3+1)=(1-6m)/(1-3m+9m^2)

hhggg1 · Answer

4/(3m+1)+(3m-7)/(27m^3+1)=(1-6m)/(1-3m+9m^2)
4/(3m+1)+(3m-7)/(3m+1)*(9m^2-3m+1)=(1-6m)/(1-3m+9m^2)
4/(3m+1)+(3m-7)/(3m+1)*(9m^2-3m+1)-(1-6m)/(1-3m+9m^2)=0
4/(3m+1)+(3m-7)-(1-6m)*(3m+1)/(3m+1)*(9m^2-3m+1)=0
4/(3m+1)+(3m-7)-(1-6m)/(9m^2-3m+1)=0
4/3m+1+3m-7-1+6m/(9m^2-3m+1)=0
4/12m-7/(9m^2-3m+1)=0
1/4*12m-7/(9m^2-3m+1)=0
12m-7/4(9m^2-3m+1)=0
12m-7/36m^2-4m+4=0