Решите в целых числах уравнение 2xy-3x+10y=32

X(2y-3) + 5(2y - 3) = 17
(x+5)(2y - 3) =17

1) x + 5 = 1 => x = -4
2y - 3 = 17 => y = 10

2) x+5 = -1 => x = -6
2y - 3 = -17 => y = -7

3) x+5 = 17 => x=12
2y-3 = 1 => y = 2

4) x+5 = -17 => x = -22
2y - 3 = -1 => y = 1

ответ: (-4; 10), (-6; -7), (12; 2), (-22; 1)