Sin x/5 -cos4x-5^x-3x)dx вычисление интеграла

int(sin^3(4x/5)*dx)=int(sin4x/5 *sin^2(4x/5)*dx)=-5/4*int(-4/5*sin(4x/5)*dx*(1-cos^2(4x/5)))=-5/4*int( (1-cos^2(4x/5)*d(cos(4x/5))=-5/4*(cos(4x/5)-1/3*cos^3(4x/5))+C=5/12 *cos^3(4x/5)-5/4 *cos(4x/5)+C