1)4 2/5: (7/10+2 3/5) 2)5*(2/3): (4/9) 3)5/6+2 - вопрос №593763214257102352523493562344792231234118 от anastasijamak 28.10.2020 20:29

Question

Математика: 1)4 2/5: (7/10+2 3/5) 2)5*(2/3): (4/9) 3)5/6+2 3/4: 4 7/9*2 2/3-1 2/3 4)(1 1/8+1 1/2): 3: (5 1/2-9/20: 1 4/5)

anastasijamak · Answer

﻿﻿﻿﻿1) 4 2/5:(7/10+2 3/5)=4/31 д.: 7/10+2 3/5=7/10+13/5=7/10+26/10=33/102 д.: 4 2/5:(33/10)= 22/5:33/10=22/5·10/33=(2·2)/3=4/32) 5·(2/3):(4/9)=7 1/21 д.: 5·(2/3)=(5·2)/3=10/32 д.: (10/3):(4/9)=10/3·9/4=(5·3)/2=15/2=7 1/2...