(log5 2+ log2 5+2)*(log5 2-lg2)*log2 5-log5 2 - вопрос №5802445522525222552 от vvolkova 13.04.2020 02:17

Question

Математика: (log5 2+ log2 5+2)*(log5 2-lg2)*log2 5-log5 2

vvolkova · Answer

Перейдем к основанию 2(1/log(2)5+log(2)5+2)*(1/log(2)5 -1/(1+log(2)5)*log(2)5-1/log(2)5==(1+log²(2)5+2log(2)5)*(1+log(2)5-log(2)5)/[log(2)5*(1+log(2)5]*log(2)5-1/log(2)5=(1+log(2)5)²/log(2)5*1/(1+log(2)5)-1/log(2)5==(1+log(2)5)/log(2)5-1/log(2)5=(1+log(2)5-1)/log(2)5=log(2)5/log(2)5=1...