7*(4а^5+2ab)= (5xy-3x^2)*x^2= : 8b^5-2b*7b^4+3b^2-8b+0,25b*(-12)b+16 - вопрос №5770593745253228527432802512169272 от sammerosetrova 16.05.2022 10:47

Question

Математика: 7*(4а^5+2ab)= (5xy-3x^2)*x^2= : 8b^5-2b*7b^4+3b^2-8b+0,25b*(-12)b+16 9a^2b(7a^2-5ab-4b^2)

sammerosetrova · Answer

7×(4а^5+2аб)=28а^5+14аб(5ху-3х^2)×х^2=5х^3у-3х^4упростить=8б^5-14б^5+3б^2-8б-3б^2+16==16-6б^5-8б9а^2б(7а^2-5аб-4б^2)==63а^4б-45а^3б^2-36а^2б^3...