(23/36+31/63-(3/4+5/21))*(48: (3/5: 78)): (19/26+14/39-1/6)*(54|1/6: - вопрос №561637823363163345214835781926143916541684712 от маша5002 25.04.2023 01:21

Question

Математика: (23/36+31/63-(3/4+5/21))*(48: (3/5: 78)): (19/26+14/39-1/6)*(54|1/6: (8|4/7: 12/

маша5002 · Answer

1)3/4+5/21=83/84, 2)-23/36+31/63=(-1449+1116)/2268=-333/2268,
3)-333/2268-83/84=(-333-83*27)/ 2268=-(333+2241)/2268=-2574 /2268=-1.306/2268 4)3/5:7/8=24/35, 5)48:24/35=48*35/24=2*35=70, 6) - 1.306/2268*70=
=-2574*70/2268=-180180/2268=-79.1008/2268, 7)19/26+14/39=(19*39+14*26)/1014=
=(741+364)/1014=1105/1014=1.91/1014, 8)1.91/1014-1/6=(3315-507)/3042=
=2808/3042=468/507, 9)8.4/7:12/35=60/7:12/35=60*35/7*12=25,
10)54.1/6:25=325/6:25=333/6=111/2=55,5, 11)(468/507)*55,5= 468*111/507*2=
51948/1014=51.234/1014, 12) (-79.1008/2268)* 51.234/1014=(-180180/2268)*51948/1014=- 9359990640/2299752=-4070.