Решите уравнения ; ( 16б) (4x-3)(5x+8)=0 (-7x+4)(8x-9)=0 - вопрос №5616279164358074890 от Boikomariana12 03.07.2020 03:47

Question

Математика: Решите уравнения ; ( 16б) (4x-3)(5x+8)=0 (-7x+4)(8x-9)=0

Boikomariana12 · Answer

(4x-3)(5x+8)=020х^2 + 32x -15x - 24 = 020x^2 + 17x - 24 = 0D = 289 + 1920 = 2209x1 = (-17 + 47)/40 = 3/4 = 0.75x2 = (-17 - 47)/40 = -1.6(-7x+4)(8x-9)=0-56x^2 + 63x + 32x - 36 = 0-56x^2 + 95x - 36 = 0D = 9025 - 8064 = 961x1 = (-95 + 31)/112 = 64/112 = 4/7x2 = (-95 - 31)/112 = -1.125...