4sinα-3cosα 5sinα если: а) tgα=2; b) ctgα=3 - вопрос №519708943523 от kseniyvolcova 11.10.2020 19:34

Question

Математика: 4sinα-3cosα 5sinα если: а) tgα=2; b) ctgα=3

kseniyvolcova · Answer

А) tg(a) = sin(a)/cos(a);tg(a) = 2; sin(a) = 2cos(a);cos(a) = x; sin(a) = 2x;(3*2x - 3x)/(5*2x) = 3x/10x = 3/10.b) ctg(a) = cos(a)/sin(a);ctg(a) = 3; cos(a) = 3sin(a);sin(a) = y; cos(a) = 3y;(3y - 3*3y)/5y = -6y/5y = -6/5....