А) 2(4–9d)–(2d+3)=–8(4–d)+3(1+2d) б) 5(2–3b)–4(6+2b)=28–(b–2) - вопрос №4864104249238431252346228223468 от djuraev488 25.04.2022 17:44

Question

Математика: А) 2(4–9d)–(2d+3)=–8(4–d)+3(1+2d) б) 5(2–3b)–4(6+2b)=28–(b–2) в) –2(3x+4)+(6x+8)=4(5x–2–(5x+8) г) 8(4–3y)–(7–2y)=–(6+3y)+8(y–2)

djuraev488 · Answer

A) 2(4-9d)-(2d+3)=-8(4-d)+3(1+2d)8-18d-2d-3=-32+8d+3+6d5-20d=-29+14d14d+20d=29+534d=34d=34:34d=1b) 5(2-3b)-4(6+2b)=28-(b-2)10-15b-24-8b=28-b+2-14-23b=30-b23b-b=-30-1422b=-44b=-44:22b=-2c)-2(3x+4)+(6x+8)=4(5x-2)-(5x+8)-6x-8+6x+8=20x-8-5x-80=15x-1615x=16x=16:15d) 8(4-3y)-(7-2y)=-(6+3y)+8(y-2)32-24y-7+2y=-6-3y+8y-1625-22y=5y-2222y+5y=25+2227y=47y=47:27...