Выражение (6+1)(6^2+1)(6^4+1)(6^8+1)(6^16+1)-0,2*6^32 - вопрос №482061861621641681616102632 от Alyyya 28.12.2022 23:41

Question

Математика: Выражение (6+1)(6^2+1)(6^4+1)(6^8+1)(6^16+1)-0,2*6^32

Alyyya · Answer

(6+1)(6^2+1)(6^4+1)(6^8+1)(6^16+1)-0.2*6^32=
((6-1)/(6-1))(6+1)(6^2+1)(6^4+1)(6^8+1)(6^16+1)-0.2*6^32=
(6²-1)(6²+1)(6^4+1)(6^8+1)(6^16+1)/5 -0.2*6^32=
(6^4-1)(6^4+1)(6^8+1)(6^16+1)/5-0.2*6^32=
(6^8-1)(6^8+1)(6^16+1)/5-0.2*6^32=
(6^16-1)(6^16+1)/5-0.2*6^32=
(6^32-1)/5-(6^32)/5=-1/5=-0.2
Выражение (6+1)(6^2+1)(6^4+1)(6^8+1)(6^16+1)-0,2*6^32

Выражение (6+1)(6^2+1)(6^4+1)(6^8+1)(6^16+1)-0,2*6^32