2log(x²-4x+5)²(4x²+1)≤log(x²-4x+5)(3x³+4x+1) ОДЗ x²-4x+5>0;D=16-20=-4<0⇒x∈(-∞;∞) x²-4x+5≠1⇒x²-4x+4≠0⇒(x-2)²≠0⇒x≠2 3x²+4x+1>0;D=16-12=4;x1=(-4-2)/6=-1 U x2=(-4+2)/6=-1/3⇒x<-1 U x>-1/3 x∈(-∞;-1) U (-1/3;2) U (2;∞) log(x²-4x+5)(4x²+1)≤log(x²-4x+5)(3x³+4x+1) (4x²+1)≤(3x³+4x+1) x²-4x≤0⇒x(x-4)≤0⇒0≤x≤4 x∈[0;2) (2;4]
ОДЗ
x²-4x+5>0;D=16-20=-4<0⇒x∈(-∞;∞)
x²-4x+5≠1⇒x²-4x+4≠0⇒(x-2)²≠0⇒x≠2
3x²+4x+1>0;D=16-12=4;x1=(-4-2)/6=-1 U x2=(-4+2)/6=-1/3⇒x<-1 U x>-1/3
x∈(-∞;-1) U (-1/3;2) U (2;∞)
log(x²-4x+5)(4x²+1)≤log(x²-4x+5)(3x³+4x+1)
(4x²+1)≤(3x³+4x+1)
x²-4x≤0⇒x(x-4)≤0⇒0≤x≤4
x∈[0;2) (2;4]