Решить. (4/9-11/15+2/3)÷3 2/5+2/9 ; (4 2/7÷3 - вопрос №340169749111523325294273314846113 от nadezhdacvoboda 25.10.2021 19:44

Question

Математика: Решить. (4/9-11/15+2/3)÷3 2/5+2/9 ; (4 2/7÷3 3/14-8+4 6/11)×3

nadezhdacvoboda · Answer

(4/9-11/15+2/3)÷3 2/5+2/9 =(20/45-33/45+30/45)÷17/5+2/9 =
=17/45*5/17+2/9 =1/9*1/1+2/9 =1/9+2/9=3/9=1/3

(4 2/7÷3 3/14-8+4 6/11)×3=(30/7÷45/14-8+4 6/11)×3=(30/7*14/45-8+4 6/11)×3=
=(2/1*2/3-8+4 6/11)×3=(4/3-8+4 6/11)×3=(1 1/3-8+4 6/11)×3=
=(1 11/33-8+4 18/33)*3=(5 29/33-8)*3=-2 4/33*3=-70/33*3=-70/11=-6 4/11