((32/57+27/38)•19/29+(25/26+48/65)•10/51+(74/75+49/50)•15/59)•3/5 - вопрос №278921832572738192925264865105174754950155935 от ludarudenko98 28.09.2020 06:08

Question

Математика: ((32/57+27/38)•19/29+(25/26+48/65)•10/51+(74/75+49/50)•15/59)•3/5

ludarudenko98 · Answer

32/57+27/38=(64+81)/114=145/114145/114*19/29=5/625/26+48/65=(125+96)/130=221/130221/130*10/51=221/663=1/374/75+49/50=(148+147)/150=295/150=59/3059/30*15/59=1/25/6+1/3+1/2=(5+2+3)/6=10/610/6*3/5=1...