Пошаговое объяснение:
2+3i3−2i(3+2-3+2i)=6+13i+6i29−4i2
Recall that since i=√−1
, it's true that i2=−1 .=6+13i+6(−1)9−4(−1)=13i13=i
Пошаговое объяснение:
2+3i3−2i(3+2-3+2i)=6+13i+6i29−4i2
Recall that since i=√−1
, it's true that i2=−1 .=6+13i+6(−1)9−4(−1)=13i13=i