HOД(48:240;264)= A)3 в)2 C)24 Д)48

48 | 2

24 | 2

12 | 2

6 | 2

3 | 3

1

48 = 2^4 * 3

240 | 2

120 | 2

60 | 2

30 | 2

15 | 3

5 | 5

240 = 2^4 * 3 * 5

264 | 2

132 | 2

66 | 2

33 | 3

11 | 11

264 = 2^3 * 3 * 11

Нод(48, 240, 264) = 2^3 * 3 = 24

ответ: C)