2+3tg(2x+п/3)=4 нужно решить

ответ: x = (arctg(2/3))/2 - π/6 + (πk)/2, k є Z

2+3tg(2x+π/3) =4

3tg(2x+π/3) = 2

tg(2x+π/3) = 2/3

2x + π/3 = arctg(2/3) + πk, k є Z

2x = arctg(2/3) - π/3 + πk, k є Z

x = (arctg(2/3))/2 - π/6 + (πk)/2, k є Z