(5х+1,6)(3х-11)=0
15x²-50,2x-17,6=0
D = -50,2²-4·15·(-17,6) = 2520,04+1056 = 3576,04 = 59,8²
x_{1} = \frac{50,2+59,8}{2*15} = \frac{110}{15} = \frac{22}{3}x
1
=
2∗15
50,2+59,8
15
110
3
22
x_{2} = \frac{50,2-59,8}{2*15} = \frac{-9,6}{15} = -0,64x
2
50,2−59,8
−9,6
=−0,64
(5х+1,6)(3х-11)=0
15x²-50,2x-17,6=0
D = -50,2²-4·15·(-17,6) = 2520,04+1056 = 3576,04 = 59,8²
(5х+1,6)(3х-11)=0
15x²-50,2x-17,6=0
D = -50,2²-4·15·(-17,6) = 2520,04+1056 = 3576,04 = 59,8²
x_{1} = \frac{50,2+59,8}{2*15} = \frac{110}{15} = \frac{22}{3}x
1
=
2∗15
50,2+59,8
=
15
110
=
3
22
x_{2} = \frac{50,2-59,8}{2*15} = \frac{-9,6}{15} = -0,64x
2
=
2∗15
50,2−59,8
=
15
−9,6
=−0,64