1) 27 = 3^3
2) 4 = 2^2
3) (3^3 * 2^2)^1\6 = 3^(3*1\6) * 2^(2*1\6) = 3^1\2 * 2^1\3
4) 3^1\2*2^1\3 - 3^1\2*2^1\3 = 0
=(3^3*2^2)^(1/6) - 3^(3/6)*2^(2/6)=
=3^(3/6)*2^(2/6) - 3^(3/6)*2^(2/6)=0
1) 27 = 3^3
2) 4 = 2^2
3) (3^3 * 2^2)^1\6 = 3^(3*1\6) * 2^(2*1\6) = 3^1\2 * 2^1\3
4) 3^1\2*2^1\3 - 3^1\2*2^1\3 = 0