4х – 5 3x + 1 3x + 7 x + 15 4 + 12х 7 + 13х 7 – 4х - вопрос №168028674531371541271374623 от Karumi1 16.07.2020 20:13

Question

Математика: 4х – 5 3x + 1 3x + 7 x + 15 4 + 12х 7 + 13х 7 – 4х 6х – 23 4∙(x – 3) + 5x 3x 2∙(3x + 1) – x 3∙(x + 4) 7x + 4∙(x – 2) 6∙(1 + 3x) 8 + 5х ≤ 3∙(7 + 2х)

Karumi1 · Answer

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4х – 5 < 3x + 1 3x + 7 > x + 15 4 + 12х > 7 + 13х 7 – 4х < 6х – 23 4∙(x – 3) + 5x 3x 2∙(3x + 1) – x 3∙(x + 4) 7x + 4∙(x – 2) > 6∙(1 + 3x) 8 + 5х ≤ 3∙(7 + 2х)

4х – 5 < 3x + 1 3x + 7 > x + 15
4 + 12х > 7 + 13х
7 – 4х < 6х – 23
4∙(x – 3) + 5x 3x
2∙(3x + 1) – x 3∙(x + 4)
7x + 4∙(x – 2) > 6∙(1 + 3x)
8 + 5х ≤ 3∙(7 + 2х)