Cos(3x-п/3)=√2/2
РЕШИТЕ УМОЛЯю НАДО​

ответ:Cos (x – π/3) = √2/2;

1) (x – π/3) = π/4 + 2 * π * n; n ϵ Z;

2) (x – π/3) = -π/4 + 2 * π * n; n ϵ Z;

Теперь найдем сами корни уравнения:

1) (x – π/3) = π/4 + 2 * π * n; n ϵ Z;

x = π/4 + п/3 + 2 * π * n;  

x = (7 * п)/12 + 2 * п * n, n ϵ Z;

2) (x – π/3) = -π/4 + 2 * π * n;  

x = -π/4 + π/3 + 2 * π * n;  

x = п/12 + 2 * п * n, n ϵ Z;

Пошаговое объяснение: