3)3/2[х]-8,5 +[x]= 0;2)1,1[х]+4,9[х]=27;4)12/5[х]-3,8+9/1[х]=0; - вопрос №141364643328502114927412538910 от ladysachenko20 26.02.2020 20:58

Question

Математика: 3)3/2[х]-8,5 +[x]= 0;2)1,1[х]+4,9[х]=27;4)12/5[х]-3,8+9/1[х]=0;​

ladysachenko20 · Answer

1 2х=13х=6,53.3/2х+х=8,52,5х=8,5х=3,42. 6х=27х=4,54.12/5х+9/1х=3,82,4х+9х=3,811,4х=3,8х=1/3...

3)3/2[х]-8,5 +[x]= 0;2)1,1[х]+4,9[х]=27;4)12/5[х]-3,8+9/1[х]=0;​