1)79/80-(3/16+39/80); 2)2/45+(41/45-7/9); 3(7/15-(2/15+1/5); - вопрос №1017070517980316398022454145793715215154316151658 от ewenchester 09.06.2023 07:06

Question

Математика: 1)79/80-(3/16+39/80); 2)2/45+(41/45-7/9); 3(7/15-(2/15+1/5); 4)3/16+(15/16-5/8)​

ewenchester · Answer

1)79/80-(3*5/16*5+39/80)==79/80-(15+39)/80==(79-54)/80=25/80=5/162)2/45+(41*1/45*1-7*5/9*5)==2/45+41/45-35/45==8/453)7/15-(2*1/15+1*3/5*3)==7/15-(2+3)/15==(7-5)/15=2/154)3/16+(15*1/16*1-5*2/8*2)==3/16+(15-10)/16=(3+5)/16==8/16=1/2=0,5...

1)79/80-(3/16+39/80); 2)2/45+(41/45-7/9); 3(7/15-(2/15+1/5); 4)3/16+(15/16-5/8)​

1)79/80-(3/16+39/80);
2)2/45+(41/45-7/9);
3(7/15-(2/15+1/5);
4)3/16+(15/16-5/8)