2С₄H₁₀ + 13O₂ --- 8CO₂ + 10H₂O
V (C₄H₁₀) = 35 л
n (C₄H₁₀) = V/Vm = 35/22,4 = 1,5625 л
n (O₂) = 1,5625*13/2 = 10,15625 л
V (O₂) = Vm*n = 22,4*10,15625 = 227,5 л
ответ: 227,5 л
2С₄H₁₀ + 13O₂ --- 8CO₂ + 10H₂O
V (C₄H₁₀) = 35 л
n (C₄H₁₀) = V/Vm = 35/22,4 = 1,5625 л
n (O₂) = 1,5625*13/2 = 10,15625 л
V (O₂) = Vm*n = 22,4*10,15625 = 227,5 л
ответ: 227,5 л