дано
m(CH4) = 32 g
V(O2)-?
CH4+2O2-->CO2+2H2O
M(CH4) =16 g/mol
n(CH4) = m/M = 32/16 = 2 mol
n(CH4) = 2n(O2)
n(O2) = 2*2 = 4 mol
V(O2) = n(O2) * Vm = 4*22.4 = 89.6 L
ответ 89.6 л
дано
m(CH4) = 32 g
V(O2)-?
CH4+2O2-->CO2+2H2O
M(CH4) =16 g/mol
n(CH4) = m/M = 32/16 = 2 mol
n(CH4) = 2n(O2)
n(O2) = 2*2 = 4 mol
V(O2) = n(O2) * Vm = 4*22.4 = 89.6 L
ответ 89.6 л