Впорядке уменьшения w (cu) cuso4,cu (oh)2,cuo,cu2o

Mr(CuSO4)=64+32+4*16= 160
W(Cu)=64/160=0.4=40%

Mr(Cu(OH)2)=64+2*16+2*1= 98
W(Cu)=64/98=0.65=65%

Mr(CuO)=64+16=80
W(CuO)=64/80=0.8=80%

Mr(Cu2O)=2*64+16=144
W(Cu)=128/144=0.89=89%

ответ: Cu2O, CuO, Cu(OH)2, CuSO4