дано
m(Cu(OH)2)=196
m(CuO)-?
196
Cu(OH)2-->CuO+H2O M(Cu(OH)2)=97.5
g/mol M(CuO)=79.5 g/mol
97.5
79.5
196 / 97.5 = X / 79.5
X=159.82
ответ 159.82 г
дано
m(Cu(OH)2)=196
m(CuO)-?
196
Cu(OH)2-->CuO+H2O M(Cu(OH)2)=97.5
g/mol M(CuO)=79.5 g/mol
97.5
79.5
196 / 97.5 = X / 79.5
X=159.82
ответ 159.82 г