Program pr_1;
var
x,y,sum, umn: integer;
begin
write ('x=');
readln (x);
write ('y=');
readln (y);
sum:=x+y;
umn:=x*y;
writeln ('sum=',sum);
writeln ('umn=',umn);
readln;
end. x=25 y=33

Question

Информатика: Program pr_1; var x,y,sum, umn: integer; begin write ( x= ); readln (x); write ( y= ); readln (y); sum:=x+y; umn:=x*y; writeln ( sum= ,sum); writeln ( umn= ,umn); readln; end. x=25 y=33

Настёна30072003 · Answer

8 раз отвечаю на этот вопрос)Результат:x=y=sum=58umn=825...

Program pr_1; var x,y,sum, umn: integer; begin write ('x='); readln (x); write ('y='); readln (y); sum:=x+y; umn:=x*y; writeln ('sum=',sum); writeln ('umn=',umn); readln; end. x=25 y=33

Program pr_1;
var
x,y,sum, umn: integer;
begin
write ('x=');
readln (x);
write ('y=');
readln (y);
sum:=x+y;
umn:=x*y;
writeln ('sum=',sum);
writeln ('umn=',umn);
readln;
end. x=25 y=33