решение
[-2; 0] ∫ (3-2x-x^2) dx = 3x -x^2 - 1/3 x^3 [-2; 0] =
= 3(0-(-2)) - (0^2 -(-2)^2) - 1/3 (0^3 -(-2)^3) = 22/3
ответ
22/3
решение
[-2; 0] ∫ (3-2x-x^2) dx = 3x -x^2 - 1/3 x^3 [-2; 0] =
= 3(0-(-2)) - (0^2 -(-2)^2) - 1/3 (0^3 -(-2)^3) = 22/3
ответ
22/3