Решите линейное уравнение: а) 1/3х = 12; в) -4х = 1/7; д)1/6у = 1/3; б) 2/3у = 9; г) 5у = -5/8; е) 2/7х = 0.

a) 1/3x = 12 => x = 12 • 3 = 36;
б) 2/3y = 9 => у = 9 • 3/2 = 13,5;
в) -4х = 1/7 => x = -1/7•4 = -1/28;
г) 5y = -5/8 => y = -5/8•5 = -1/8;
д) 1/6y = 1/3 => y = 1/3 • 6 = 2;
e) 2/7x = 0 => х = 7/2 • 0 = 0.